InterviewSolution
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InterviewSolution
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The values of ` K_(p_(1)) and K_(p_(2))` for the reactions `X hArr Y+Z" " ` …(1) and `A hArr 2 B " " ` …(2) are in the ratio of 9:1 .If the drgree of dissociation kof X and A be equal , then total pressure at equilibrium (1) and (2) are in the ratioA. `3:1`B. `1:9`C. `36:1`D. `1:1` |
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Answer» Correct Answer - C Suppose total pressure at equilibrium for reactions (1) and (2) are `P_(1) and P_(2)` respectively . Then `{: (,X,hArr,Y,+,Z), (" Intial",1 "mole",,0,,0), ("At eqm",1-alpha,,alpha,,alpha"Total"=1+alpha), (,p_(X)=(1-alpha)/(1+alpa)P_(1),,p_(Y)=alpha/(1+alpha)P_(1),,p_(Z) =alpha/(1+alpha)P_(1)):}` ` K_(p_(1))= (alpha/(1+alpha)P_(1))^(2)/((1-alpha)/(1+alpha)P_(1)) = (alpha^(2) P_(1))/(1-alpha^(2))cong alpha^(2)P_(1)` `{: ( ,A,hArr,2B,) , (" Intial" ,1 "mole",,0,) ,(" At eqm" ,1-alpha,,2 alpha,"Total" = 1+alpha):}` `p_(A) = (1-alpha)/(1+alpha)P_(2), p_(B) = (2alpha)/(1+alpha)P_(2)` `K_(p_(2))=(((2alpha)/(1+alpha)P_(2)))/((1-alpha)/(1+alpha)P_(2)) = (4alpha^(2))/(1-alpha^(2))P_(2)= 4 alpha^(2)P_(2)` ` K_(p_(1))/K_(p_(2)) = (alpha_(2)P_(1))/(4 alpha^(2)P_(2))=P_(1)/(4 P_(2))=9/1 ` (Given ) or ` (P_(1))/(P_(2))=36/1 = 36*1` |
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