The values of K_(P1) and K_(P2) for the reactions : X hArr Y + Z and A hArr 2B are in the ratio 9 : 1 if degree of dissociation and initial concentration of X and A be equal then total pressure at equilibrium P_1, and P_2 are in the ratio

The values of K_(P1) and K_(P2) for the reactions : X hArr Y + Z and A

1.	The values of K_(P1) and K_(P2) for the reactions : X hArr Y + Z and A hArr 2B are in the ratio 9 : 1 if degree of dissociation and initial concentration of X and A be equal then total pressure at equilibrium P_1, and P_2 are in the ratio
Answer» `36:1` `1:1` `3:1` `1:9` SOLUTION : `K_(P_1)/K_(P_2) = (P_yP_z)/(P_x) XX P_A/P_B^2` `K_(P_1)/K_(P_2) = [((x/(a+x))P_1 (x/(a+x))P_1)/(((a-x))/((a+x))xxP_1)]xx[(((a-x))/((a+x))P_2)/((4x^2P_2^2)/((a+x)^2))]` `=((x^2P_1)/((a+x)(a-x)))xx(((a-x)(a+x))/(4x^2P_2))` `K_(P_1)/K_(P_2) = P_1/(4P_2)` Given that `K_(P_1)/K_(P_2) = 9/1` `:. 9.1 = P_1 /(4P_2) rArrP_1/P_2 = 36/1`