The values of Kp_(1) and Kp_(2) for the reaction given below are in the ratio 2: 1. If degree of dissociation of X and A are equal, then total pressure of equilibrium (1) and cquilibrium (2) are in the ratio X hArr Y + Z , Kp_(1) : A hArr 2B : Kp_(2)

The values of Kp_(1) and Kp_(2) for the reaction given below are in th

1.	The values of Kp_(1) and Kp_(2) for the reaction given below are in the ratio 2: 1. If degree of dissociation of X and A are equal, then total pressure of equilibrium (1) and cquilibrium (2) are in the ratio X hArr Y + Z , Kp_(1) : A hArr 2B : Kp_(2)
Answer» Solution :`UNDERSET(1-alpha_(1))(X) HARR underset(alpha_(1))(Y)+underset(alpha_(1))(Z)` `Kp_(1)=(((alpha_(1))/(1+alpha_(1)).p_(1)) xx ((alpha_(1))/(1+alpha_(1)).p_(1)))/(((1-alpha_(1))/(1+alpha_(1)) xx p_(1)))` `KP=(alpha_(1)^(2) xx p_(1))/(1-alpha_(1)^(2))` ...(1) `underset(1-alpha_(1))(A) harr underset(2alpha_(1))(2B), Kp_(2)` `Kp_(2)=(((2alpha_(1))/(1+alpha_(1)) xx p_(2))^(2))/((1-alpha_(1))/(1+alpha_(1)) xx p_(2)), Kp_(2)=(4alpha_(1)^(2) xx p_(2))/(1-alpha_(1)^(2))` ...(2) `((1))/((2))(Kp_(1))/(Kp_(2))=(1)/(4) xx (p_(1))/(p_(2)) IMPLIES (p_(1))/(p_(2))=4 xx (Kp_(1))/(Kp_(2))=4 xx 2=8`