1.

The values of Ksp of CaCO_(3) and CaC_(2)O_(4) are 4.7 xx 10^(-9) and 1.3 xx 10^(-9) respectively at 25^(@)C. If the mixture of these two is washed with water, what is the concentration of Ca^(2+) ions in water

Answer»

`5.831 xx 10^(-5)M`
`6.856 xx 10^(-5)M`
`3.606 xx 10^(-5) M`
`7.746 xx 10^(-5) M`

Solution :`CaCO_(3) RARR underset(X)(Ca^(2+)) + underset(x)(CO_(3))^(2-)`
`CaC_(2)O_(4) rarr underset(y)(Ca^(2+)) + underset(y)(C_(2)O_(4))^(2-)`
Now, `[Ca^(2+)] = x + y`
and `x(x+y) = 4.7 xx 10^(-9)`
`y(x+y) = 1.3 xx 10^(-9)`
On solving we GET
`[Ca^(2+)] = 7.746 xx 10^(-5)M`.


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