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The values of observed and calculated molecular weights of silver nitrate are `92.64` and `170` respectively.The degree of dissociation of silver nitrate is:A. 0.6B. 0.835C. 0.467D. 0.6023 |
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Answer» Correct Answer - B `alpha = (i-1)/(n^(l) - 1)` For `AgNO_(3), n^(l) = 1 :. alpha = (i-1)/(2-1) :. alpha = i-1``"But" i="normal molar mass."/"observed molar mass."` `:. alpha = 170/92.64 - 1 = 0.835` `:. % alpha = 0.835 xx 100 = 83.5 %` |
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