InterviewSolution
`2^(1//4)CIS[(2kpi+pi//6)/(4)],k=0,1,2,3``2^(1//4)cis[(2kpi+pi//3)/(4)],k=0,1,2,3``2^(1//4)cis[(2kpi-pi//6)/(4)],k=0,1,2,3``2^(1//4)cis[(2kpi-pi//3)/(4)],k=0,1,2,3`
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