1.

The values of the rate constant of the reaction C_(2)H_(5)I+OH^(-)toC_(2)H_(5)OH+I^(-) at 30^(@) and 60^(@)C temperatures are 0.325 and 6.735 litre "mole"^(-1) "second"^(-1) than what will be the value of activation energy?

Answer»

20260 cal
20260 K cal
361.44 cal
84773 cal

Solution :`(logK_(2))/(K_(1))=(E_(a))/(2.303R)((1)/(T_(1))-(1)/(T_(2)))`
`therefore (LOG 6.735)/(0.325)=(E_(a))/(2.303)xx1.987((1)/(303)-(1)/(333))`
`therefore E_(a)`=20260 cal


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