1.

The values of `wedge_(m)^(oo)` for`NH_(4)Cl,NaOH,` and `NaCl` are, respectively, `149.74,248.1`,and `126.4 ohm^(-1)cm^(2)eq^(-1)`. The value of `wedge_(eq)^(oo)NH_(4)OH` isA. ` 371.44`B. ` 271.44`C. ` 71. 44`D. It cannot be calculated from the data given

Answer» Correct Answer - B
`Lambda_(eq)^(infty) ` or ` Lambda_(CH_4OH)^(infty) = Lambda_(eq_(NH_4Cl))^(infty) + Lambda_(eq_(NaOH)^(infty) -Lambda(eq_(NaCl))^(infty)`
` = (149. 74 + 248.1 - 126.4) = 271. 44 "ohm"^(-1) cm^2 eq^(-1)`.


Discussion

No Comment Found

Related InterviewSolutions