The. van der Waal's equation of law of corresponding states for 1 mole

1.	The. van der Waal's equation of law of corresponding states for 1 mole of gas is :
Answer» `(pi + 3/(phi^2)) (3 phi - 1) = 8 theta` `(pi + 3/(phi))(3 phi - 1) = 8 theta` `(pi + 3/(phi)) (3 phi + 1) =8 R theta` `(pi + 3/(phi)) (3 phi - 1) = 8 R theta` Solution :`(P- a/(V^2) (V - B) = RT` `P = pi P_C = (pi .a)/(27 b^2 ) , V = phi , V_C = 3bphi` `T = theta T_C = (a theta)/(27 Rb)` `IMPLIES ((pi a)/(27 b^2) + a/(9 b^2 phi^2)) (3 b phi - b) = (R xx a theta)/(27 Rb)` `implies (pi + 3/(phi^2)) (3 phi - 1) = 8 phi`.

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