The van der Waal's equation of state for 1 mole real gas is (P + (a)/(V^(2))) (v - b) = RT....(i) The Virial equation for 1 mole real gas is PV = RT [1 + (x)/(V) + (y)/(V^(2)) + (z)/(V^(3))+....." To higher power of " V] ....(ii) when x, y and z are constants which are known as 2nd, 3rd adn 4th co-efficients respectively. The temperature at which real gas obeys ideal gas equation i.e., (PV = nRT) is known as Boyle's temperature. Answer the following questions on the basis of the above write up : The third virial coefficient of He gas is 4 xx 10^(-2) ("litre/mole")^(2), then what will be volume of 2 mole He gas at NTP

The van der Waal's equation of state for 1 mole real gas is (P + (a)/(

1.	The van der Waal's equation of state for 1 mole real gas is (P + (a)/(V^(2))) (v - b) = RT....(i) The Virial equation for 1 mole real gas is PV = RT [1 + (x)/(V) + (y)/(V^(2)) + (z)/(V^(3))+....." To higher power of " V] ....(ii) when x, y and z are constants which are known as 2nd, 3rd adn 4th co-efficients respectively. The temperature at which real gas obeys ideal gas equation i.e., (PV = nRT) is known as Boyle's temperature. Answer the following questions on the basis of the above write up : The third virial coefficient of He gas is 4 xx 10^(-2) ("litre/mole")^(2), then what will be volume of 2 mole He gas at NTP
Answer» 22.0 litres 44.0 LITRE 44.8 litre 45.3 litre Solution :`b^(2) = 4 xx 10^(-2)` litre/mole i.e., `b = 2 xx 10^(-1)` litre/mole EXTENDED volume for 2 mole REAL gas. `:. V_("real") = V_(C) + nb = 44.8 + 0.4 = 45.3` litre