The van der Waals constant 'b' for oxygen is 0.0318 L mol^(-1). Calculate the diameter of the oxygen molecule.

The van der Waals constant 'b' for oxygen is 0.0318 L mol^(-1). Calcul

1.	The van der Waals constant 'b' for oxygen is 0.0318 L mol^(-1). Calculate the diameter of the oxygen molecule.
Answer» Solution :b=4 vor`v=(b)/(4)=(0.0318)/(4)=7.95xx10^(3) L MOL^(-1)=7.95 cm^(3) mol^(-1)` `:. "Volume occupied by one " O_(2) " molecule"=(7.95)/(6.02xx10^(23))=1.32xx10^(-23)cm^(3)` Cosidering the molecule to be SPHERICAL, `(4)/(3)pi r^(3)=1.32xx10^(-23)" or " r^(3)=3015xx10^(-24)` `:. 3 log r=log(3.15xx10^(-24))=-24+0.4983=-23.5017` or`log r=-7.8339=bar(8).1661` `:. "Diameter of oxygen molecule "=2xxr=2xx1.466xx10^(-8)cm=2.932xx10^(-8)cm=2.932Å`