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The van der Waals constant `b` of `Ar` is `3.22xx10^(-5) m^(3) mol^(-1)`. Calculate the molecular diameter of `Ar`. |
Answer» Use `b=4xx`volume occupied by the molecules in `1 mol` of a gas `b=4xxN_(0)xx((4)/(3)pi r^(3))` `3.22xx10^(-5)=4xx6.023xx10^(23)xx(4)/(3)xx(22)/(7)xxr^(3)` `r=[(3.22xx10^(-5)xx3xx7)/(4xx6.023xx10^(23)xx4xx22)]^(1//3)` `=0.1472xx10^(-9)m=0.1472 nm` `d=2r=0.2944 nm` |
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