1.

The Van't Hoff factor for calcium nitrate (Ca(NO_(3))_(2) is 2.5 . Using the dissociation equilibrium, Ca(NO_(3))_(2) hArr Ca^(2+)+2NO_(3)^(-) the degree of dissociation is :

Answer»

0.25
0.33
0.66
0.75

Solution :`CA(NO_(3))_(2) hArr Ca^(2+)+2NO_(3)^(-)`
If a is the degree of dissociation,
`1-alpha "" alpha""2ALPHA`
Total no. of particles after dissociation
`=1-alpha+alpha+2alpha=1+2alpha`
Van.t HOFF factor `=(1+2 alpha)/(1)=2.5`
`:.2 alpha=1.5`or`alpha=(1.5)/(2)=0.75`


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