1.

The vapour density of a mixture containing NO_(3) and N_(2)O_(4) is 38.3 at 27^(@)C Calcualte the moles of NO_(2) in 100g of the mixture.

Answer»

Solution :Mol. Mass of mixture `=2xx38.3=76.6`
No. of MOLES in 100g of mixture `=(100)/(76.6)`
LET a g of `NO_(2)` is present in mixture.
Moles of `NO_(2)+` moles of `N_(2)O_(4)=` Moles of mixture
`(a)/(46)+(100-a)/(92)=(100)/(76.6)` or `a=20.10g`
Moles of `NO_(2)` in mixture `=(20.10)/(46)=0.437`.


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