The vapour density of completely dissociated NH_(4)Cl is
Answer»
double than that of `NH_(4)Cl` half than that of `NH_(4)Cl` same as that of `NH_(4)Cl` DETERMINED by the amount of solid `NH_(4)Cl` taken
Solution :`NH(4)Cl to NH_(3) + HCl .` Thus , 1 mole of `NH_(4)Cl` on DISSOCIATIONPRODUCES 2 moles of the vapour (1 mole `NH_(3)` and 1 mole HCl) which will have double the volume at the same temperature and pressure . As density `prop 1//volume` , therefore density will be halved .