1.

The vapour pressure of a solution cont.aning 10 g of a non-electrolyte in 200 g of water at a particular temperature is 2985 Pa. The vapour pressure of pure water at that temperature is 3000 Pa. Calculate the molecular mass of the solute.

Answer»

Solution :`(P^(0) - P)/(P^(0)) = (M_(2) W_(1))/(W_(2)M_(1))`
`(3000 - 2985)/(3000) = (10x 18)/(M_(2) XX 200) `
`M_(2) = (10 xx 18 xx 3000 )/(200 xx 15 )`
`mu_(2) `= 180 .


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