InterviewSolution
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InterviewSolution
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The vapour pressure of a solution prepared by dissolving 1 mol of liquid A and 2 mol of liquid B has been found to be 38 torr. The vapour pressure of pure A and pure B are 45 and 36 torr respectively. The solution |
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Answer» shows negative deviation `p_(A)=x_(A) p_(A)^(@) = (1)/(3) xx 45 = 15` torr `p_(B) = x_(B)p_(B)^(0) =(2)/(3) xx 36 = 24` torr Total PRESSURE = 15+24=39 torr The observed pressure is less than expected valueand hence it shows negative deviation. |
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