1.

The vapour pressure of a solvent at 293 K is 100 mm Hg. The vapour pressure of a solution containing 1 mole of strong electrolyte (AB_(2)) in 99 moles of the solvent at 293 K is (assume comlete dissociation of the solute).

Answer»

103 MM HG
99 mm Hg
97 mm Hg
101 mm Hg

Solution :According to Raoult's Law
`(P_(A)^(@)-P_(S))/P_(S)="i"n_(B)/n_(A)`
`AB_(2)overset((AQ))toA^(+)(aq)+2B^(-)(aq)`
`i=(1-alpha+nalpha)/1=(1-1+3xx1)/1=3`
`P_(S)^(@)/P_(S)=1+0.03=1.03`
`P_(S)=P_(A)/(1.03)=((100mm))/((1.03))=97.0mm`


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