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The vapour pressure of acetone at `20^(@)C` is 185 torr. When `1.2 g` of non-volatile substance was dissolved in `100g` of acetone at `20^(@)C` its vapour pressure was 183 torr. The moalr mass `(g mol^(-1))` of the substance is:A. 32B. 64C. 128D. 488 |
Answer» Correct Answer - B `(P_(@)-P_(S))/(P_(S))=(n)/(N)` `(185-183)/(183)=(1.2//M)/(100//58)rArr M ~~ 64 g//mol` |
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