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The vapour pressure of ether (mol. mass = 74) is 60 kPa at 293 K. If 3g of a compound A is dissolved in 50 g of ether at this tempenture, the vapour pressure falls to 56.8 kPa. Calculate molecular mass of A. |
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Answer» <P> Solution :`P^(0) = 60` kPaP = 56.8 kPa `W_(2) = 3g ` `W_(1) = ` 50 g `M_(2) ` = 9 `M_(1)= 74 ` `M_(2)= (W_(2))/(W_(1)) xx M_(1) xx (P^(0))/(P^(0) - P) ` = `(3)/(50) xx 74 xx (60)/(60 - 56.8)` `M_(2) = 83.25` `therefore` MOLECULAR MASS of A = 83.25. |
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