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The vapour pressure of fluorobenzene at `t^(@)` C is given by the equation log p (mm Hg)= `7.0-(1250)/(t+220)` Calculate the boiling point of the liquid in `C^(@)` if the external (applied) pressure is `5.26%` more than required for normal boiling point(log2=0.3) |
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Answer» Correct Answer - 85 `1.0526xx760=p_(ext)` `p_(ext)=799.976=800` Torr `:. "log" 800=7-1250/(t+220)` `implies 2.9=7-1250/(t+220)impliest=84.878^@C` |
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