1.

The vapour pressure of mixture of ethanol and propanol is 290 mm at 300 K temp. If the vapour pressure of propanol is 200 mm at 300 K temp. and the mole fraction of ethanol is 0.6, then what will be the vapour pressure of ethanol at 300 K temp. ?

Answer»

350 MM
300 mm
700 mm
360 mm

Solution :`P=P_(A)^(@).X_(A)+P_(B)^(@).X_(B)`
`290=200xx0.4+P_(B)^(@)xx0.6`
`P_(B)^(@)=350 mm`


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