1.

The vapour pressure of pure liquid A and B are 520 mm and 1000 mm respectively at 80^(@)C temp. If the solution of A and B is boil at 80^(@)C temp. and I at pressure, what will be the % of A in the mixture ?

Answer»

`52%`
`34%`
`48%`
`50%`

Solution :`P=P^(@)x_(A)+P^(@)x_(B)`
`760=(520xx x_(A))+[1000(1-x_(A))]`
`520xx x_(A)+1000-1000 x_(A)`
`therefore x_(A)=0.5`
`therefore %` mole `= 0.5xx100`
= 50%


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