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The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour [ressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-A. 0.31B. 0.38C. 0.62D. 0.76 |
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Answer» Correct Answer - B `P_(s)=X_(A)P_(A)^(@)+X_(B)P_(B)^(@)` `P_(s)=X_(A)P_(A)^(@)+(1-X_(A))P_(B)^(@)` `:.580=X_(A)xx440+(1-X_(A))720` `140=280X_(2)"and"X_(A)=0.5` `Y_(A)=(P_(A))/(P_(S))=(0.5xx440)/(580)=0.38` |
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