1.

The vapour pressure of pure liquid A is 40 mm Hg at 310 K. The Vapour pressure of this liquid in solution with liquid with liquid B is 32mm Hg. Calculate the mole fraction of A in the solution if the mixture obeys Raoult's Law.

Answer»

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Solution :`"Vapour PRESSURE of pure liquid A "(P_(A)^(@))=40MM.`
`"Vapour pressure of A in the solution "(P_(A))=32 mm.`
`"According to Raoults's Law" , X_(A)=P_(A)/P_(A)^(@)=((32mm))/((40mm))=0.8`


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