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The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressureof 1 molal solution of a non-volatile solute in it |
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Answer» Answer: The vapour pressure of water is 12.3 kPa at 300 K. We need to CALCULATE the vapour pressure of 1 molal solution of a non-volatile solute in it. 1000 g of water contains 1 MOLE of solute. The MOLAR mass of water is 18 g/mol. Number of moles of water = 18 1000
=55.56 mol Mole fraction of the solute in the solution is x= 1+55.56 1
=0.0177. The RELATIVE lowering in the vapour pressure is equal to the mole fraction of solute. p 0
p 0 −p
=x 12.3 12.3−p
=0.0177 ⇒p=12.08 Hence, the vapour pressure of the solution is 12.08 kPa. |
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