1.

The vapour pressure of water is 12.3 kPa at 300 K. Calculate the vapour pressure of 1 molal solution in it.

Answer»

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Solution :1 molal solution means 1 mol of the SOLUTE in 1 KG of the solvent (water).
`therefore"Mol fraction fraction of solute "=(1)/(1+55.5)=0.0177`
`"Now,"(p^(@)-p_(s))/(p^(@))=x_(2), i.e.,(12.3-p_(s))/(12.3)=0.0177"or"p_(s)="12.08 kPa."`


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