1.

The vapour pressure of water is 17.5 mm at 20^(@)C temp. what is the vapour pressure of solution 20^(@)C prepared by dissolving 18 gram glucose in to 178.2 gram water at 20^(@)C temp. ?

Answer»

<P>17.675 mm
15.750 mm
16.500 mm
17.325 mm

SOLUTION :`P_(1)^(0)=17.5 mm, P_(1)=?`
`(P_(1)^(@)-P_(1))/(P_(1)^(@))=(M_(1)w_(2))/(M_(2)w_(1))`
`(17.5-P_(1))/(17.5)=(18xx18)/(180xx178.2)`
`P_(1)=17.325 mm`


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