The vapour pressure will be lowest forA. 0.1 M sugar solutionB. 0.1 M KCl solutionC. `0.1 M Cu(NO_(3))_(2)` solutionD. `0.1 M AgNO_(3)` solution

The vapour pressure will be lowest forA. 0.1 M sugar solutionB. 0.1 M

1.	The vapour pressure will be lowest forA. 0.1 M sugar solutionB. 0.1 M KCl solutionC. `0.1 M Cu(NO_(3))_(2)` solutionD. `0.1 M AgNO_(3)` solution
Answer» Correct Answer - C Vapour pressire of a solvent is lowered by the presence of solute in it. Lowering in vapour pressure is a colligative property i.e., it depends on the no. of particles present in the solution. `Cu(NO_(3))_(2)` give the maximum no. of ions. (i.e., 3) so it causes the greatest lowering in vapour pressure of water.

Discussion

No Comment Found

Related InterviewSolutions

`K_(f)` for water is `1.86 K kg mol^(-1)`. IF your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C` ?A. 27 gB. 72 gC. 93 gD. 39 g
For a dilute solution containing `2.5 g` of a non-volatile non-electrolyte solution in `100g` of water, the elevation in boiling point at `1` atm pressure is `2^(@)C`. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of `Hg)` of the solution is: (take `k_(b) = 0.76 K kg mol^(-1))`A. 724B. 740C. 736D. 718
29.2% (W/W) HCI stock solution has a density of 1.25 g `mL^(-1)`. The molecular mass of HCI is 36.5 g `mol^(-1)` Calculate the volume (mL) of stock solution required to prepare 200 mL of 0.4 M HCIA. 2 mLB. 4 mLC. 8 mLD. 6 mL
The freezing point among the following equimolal aqueous solutions will be highest forA. `C_(6)H_(5)NH_(3)Cl` (aniline hydrochloride)B. `Ca(NO_(3))_(2)`C. `La(NO_(3))_(3)`D. `C_(6)H_(12)O_(6)` (glucose)
The amount of urea to be dissolved in 500 ml of water (K = 18.6 K `"mole"^(-1)` in 100 g solvent) to produce a depression of `0.186^(@)C` in freezing point isA. 9 gB. 6 gC. 3 gD. 0.3 g
The normality of `0.3 M` phosphorous acid `(H_(3) PO_(3))` isA. `0.1`B. `0.9`C. `0.3`D. `0.6`
Benzoic acid dissolved in benzene showsA. its normal molecular massB. Double of its normal molecular massC. Half of its normal molecular massD. Not definite.
When benzoic acid dissolve in benzene, the observed molecular mass isA. 244B. 61C. 366D. 122
Four solutions of `K_(2)So_(4)` with the concentrations 0.1m ,0.001 m, and 0.0001 mare available . The maximum value of colligative property corresponds to :A. 0.0001 m solutionB. 0.001 m solutionC. 0.01 m solutionD. 0.1 m solution
Dry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure ware. The loss in weight of solution was 2.50 gm and that of pure solvent 0.04 gm. What is the molecular weight of the soluteA. `70.31`B. `7.143`C. `714.3`D. 80

The vapour pressure will be lowest forA. 0.1 M sugar solutionB. 0.1 M KCl solutionC. `0.1 M Cu(NO_(3))_(2)` solutionD. `0.1 M AgNO_(3)` solution

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment