The vapour pressures of benzene at 303k and 333k are respectively 1.53xx10^(4) and 5.2xx10^(4)Nm^(-2) Calculate the latent heat of evaporation of benzene over this temperature.

The vapour pressures of benzene at 303k and 333k are respectively 1.53

1.	The vapour pressures of benzene at 303k and 333k are respectively 1.53xx10^(4) and 5.2xx10^(4)Nm^(-2) Calculate the latent heat of evaporation of benzene over this temperature.
Answer» SOLUTION :LOGE `P_(2)/P_(1)=(DeltaHv)/(2.30R)[(T_(2)-T_(1))/(T_(1)T_(2))]`,where `DeltaHv`is LATENT HEAT of evportation. `2.303"log" "(5.2xx10^(4))/(1.52xx10^(4))=(DeltaHv)/8.314[(333-303)/(333xx303)]` `DeltaH_(v)=34215J=34.215KJ`