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The vapour pressuress of pure solvent and solution are 120 mm and 108 mm respectively. The mole fraction of the solvent in the solution is |
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Answer» 0.1 `(P_(1)^(0)-P)/p_(1)^(0)=X_(2)` (MOLE FRACTION of solute) `(120-108)/120=X_(2)=0.1` Mole fraction of SOLVENT `=1-X_(2)=1-0.1=0.9` |
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