1.

The variable x varies directly as y and x = 80 when y = 160, What is y when x is 64.

Answer»

If x varies directly as y.

∴  x/y = k (constant)

If x = 80 and y = 160 …(i)

∴ x/y = 80/160 = 1/2

⇒ k = 1/2

When x = 64, then from Eq. (i)

64/y = 1/2

⇒ y = 64 × 2 = 128



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