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The variance offirst 50 even natural numbers is(1) `(833)/4`(2) 833(3) 437(4) `(437)/4`A. `(833)/(4)`B. 833C. 437D. `(437)/(4)` |
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Answer» Correct Answer - B Here, `bar(X) = (sumX_(i))/(n)=(2+4+6+8+ ... +100)/(50)=(50xx51)/(50)=51` ` " "[ because sum2n=n(n+1), " here " n=50]` Variance, ` sigma^(2)=(1)/(n) sumX_(i)^(2)-(bar(X))^(2)` `=(1)/(50) (2^(2)+4^(2)+ ... +100^(2))-(51)^(2)=833` |
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