1.

The vector equation of the plane which is at a distance of 3//sqrt(14) from the origin and the normal from the origin is 2hati-3hatj+hatk is

Answer»

1)`VECR.(2hati-3hatj+hatk)=3`
2}`vecr.(hati+hatj+hatk)=9`
3)`vecr.(hati+2hatj)=3`
4)`vecr.(2hati+hatk)=3`

ANSWER :A


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