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The vectors `vecA` is given by `vecA = thati - (sin pi t)hatj + t^(2)hatk` where t is time. Then which of the following isA. `|vecA|(at t = 1) = sqrt(2)`B. `(dvecA)/(dt)(at t = 1) = hati+pi hatj+2hatk`C. `|vecAxx(dvecA)/(dt)|(at t = 1) = sqrt(2pi^(2)+1)`D. `vecA. (dvecA)/(dt)(at t = 1) = 4` |
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Answer» Correct Answer - D The veloctors ………. `vecA = t hati - sin pi t hatj + t^(2)hatk` `vecA(t=1) = hati - sin pi t hat j + hatk` `|vecA| = sqrt(2)` `(dvecA)/(dt) = hati - pi cos pi t hatj + 2t hatk` `(dvecA)/(dt) (t = 1) = (hati+pi hatj + 2hatk)` `vecAxx(dvecA)/(dt) = (hati+hatk)` `|vecAxx(dvecA)/(dt)|=- sqrt(2pi^(2)+1)` `vecA.(dvecA)/(dt) = 1+2=3` |
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