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| 1. |
The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 xx 10^(5) m s^(-1). If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity? |
| Answer» Solution :`lamda = (h)/(mv) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/((0.1lh) (4.37 xx 10^(5) MS^(-1))) = 1.516 xx 10^(-28) m` | |