1.

The velocity associated with a proton moving in a potential difference of 1000 v is 4.37 x 105 ms-1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

Answer»

v = 4.37 x 105 ms-1

m = 0.1 kg

h = 6.626 x 10-34 Js

λ = h/mv

or, λ = {6.626 x 10-34}/{10-1 x 4.37 x 105}

or, λ = 6.626/4.37 x 10-38 = 1.51 x 10-38 m.



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