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The velocity associated with a proton moving in a potential difference of 1000 v is 4.37 x 105 ms-1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity. |
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Answer» v = 4.37 x 105 ms-1 m = 0.1 kg h = 6.626 x 10-34 Js λ = h/mv or, λ = {6.626 x 10-34}/{10-1 x 4.37 x 105} or, λ = 6.626/4.37 x 10-38 = 1.51 x 10-38 m. |
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