The velocity at the maximum height of a projectile is √3/2 times of its initial velocity of projection which is u=20 ms−1. Find the range of projectile on the horizontal plane.(Take g=10 m/s2)

The velocity at the maximum height of a projectile is √3/2 times of

1.	The velocity at the maximum height of a projectile is √3/2 times of its initial velocity of projection which is u=20 ms−1. Find the range of projectile on the horizontal plane.(Take g=10 m/s2)
Answer» The velocity at the maximum height of a projectile is $\sqrt{3} / 2$ times of its initial velocity of projection which is $u = 20 {ms}^{- 1}$ . Find the range of projectile on the horizontal plane. (Take $g = 10 {m/s}^{2}$ )

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The velocity at the maximum height of a projectile is √3/2 times of its initial velocity of projection which is u=20 ms−1. Find the range of projectile on the horizontal plane.(Take g=10 m/s2)

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