The velocity at the maximum height of aprojectile is sqrt(3)/2times the initial velocity of projection. The angle of projection is

The velocity at the maximum height of aprojectile is sqrt(3)/2times th

1.	The velocity at the maximum height of aprojectile is sqrt(3)/2times the initial velocity of projection. The angle of projection is
Answer» `60^(@)` `45^(@)` `30^(@)` `15^(@)` Answer :C