1.

The velocity corresponding to a gas "X" (MW=100) corresponding to the maxima of the curve given below at a given temperature is 200 m/s.Then kinetic energy of 300 gram of has "X" will be

Answer»

9000 kJ
9 kJ
90 kJ
810 kJ

Solution :The velocity CORRESPONDING to the maxima is the most probable velocity which is given by the expression
`C_(np)=sqrt((2RT)/M)`
`RT=(C_(mp)^2M)/2=((200)^2xx100xx10^(-3))/2=40000xx50xx10^(-3) J mol^(-1) = 40xx50J mol^(-1)`
No of moles =`300/100=3`
`E=3/2nRT=3/2xx3xx40xx50=9xx10^(3) J =9 kJ`


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