The velocity of a body of mass 2 kg as a function of t is given by v(t) = 2t hati + t^(2)hatj . Find the momentum and the force acting on it, at time t = 2s.

The velocity of a body of mass 2 kg as a function of t is given by v(t

1.	The velocity of a body of mass 2 kg as a function of t is given by v(t) = 2t hati + t^(2)hatj . Find the momentum and the force acting on it, at time t = 2s.
Answer» Solution :MASSOF the bodym=2 kg VELOCITYOF thebodyv (t ) = (2t )`hat(j)+ (t^(2) hat(j))` Velocityof thebodyat t= 2 s `=4hat(j ) + 4hat(j )` Momentumof body`VEC( p )=mv= 2 (4hat(j ) + 4hat(j ))` Acceleration of body `a= (d v)/( dt )` `=(d )/(dt ) (2t hat(j ) + t^(2) hat(j ))` Att =2s `(2HAT(i ) + 4hat(j ) )` FORCE acting on the body( F ) =ma `=(4hat(i )+ 8hat(j ))N`