1.

The velocity of a car increases from 36 km/h to 108 km/h in 10s. find its acceleration ​

Answer»

Answer:

<U>Given :

➡️ u = initial VELOCITY = 36km/hr

that is, u = 36×1000/3600 m/s

that is, u = 10m/s

➡️v= final velocity = 108km/hr

that is, v= 108×1000/3600m/s

that is, v= 30m/s

➡️ time = t = 10s

To find :

➡️ ACCELERATION of the car

Solution :

we know that

acceleration(a) = (v-u)/t

that is, a = (30-10)/10m/s square

that is, a = 20/10m/s square

that is , a = 2 m/s square

Hence, acceleration of the car is 2 m/s square.



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