The velocity of a cylindrical layer of liquid at a distance 0.4 cm from the axisof a tube of radius 0.5 cm is 3.6cm//s .Find the velocity of a layer lying at a distance of 0.3 cm from axis .[Hint : v=(P)/(4etal)(r^(2)-x^(2))]

The velocity of a cylindrical layer of liquid at a distance 0.4 cm fro

1.	The velocity of a cylindrical layer of liquid at a distance 0.4 cm from the axisof a tube of radius 0.5 cm is 3.6cm//s .Find the velocity of a layer lying at a distance of 0.3 cm from axis .[Hint : v=(P)/(4etal)(r^(2)-x^(2))]
Answer» SOLUTION :`r=0.5cm ""v=(P)/(4etal)(r^(2)-x^(2))and` `x_(1)=0.4cm` `x_(2)=0.3cm "" v_(1)=(P)/(4etal)(r^(2)-x_(1)^(2))`….(1) `v_(1)=3.6cm//s "" v_(2)=(P)/(4etal)(r^(2)-x_(2)^(2))`…(2) `v_(2)=?` TAKING RATIO of EQUATION (1) and (2), `(v_(1))/(v_(2))=(r^(2)-x_(1)^(2))/(r^(2)-x_(2)^(2))` `thereforev_(2)=v_(1)[(r^(2)-x_(2)^(2))/(r^(2)-x_(1)^(2))]` `v_(2)=3.6[(0.25-0.09)/(0.25-0.16)]=(3.6xx0.16)/(0.09)` `v_(2)=6.4cm//s`