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The velocity of a particle in `SHM` at the instant when it is `0.6cm` away from the mean position is `4cm//s`. If the amplitude of vibration is `1cm` then its velocity at the instant when it is `0.8cm` away form the mean postion is (in cm//s)A. `2.25`B. `2.5`C. `3.0`D. `3.5` |
Answer» Correct Answer - C `V = omega sqrt(A^(2) - x^(2))`, |
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