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The velocity of a particle is given by \( v=A \omega \cos (\omega t-k x) \), where \( x \) is position and \( t \) is time. The dimension of \( \frac{k}{\omega} \) will be(1) \( \left[ M ^{0} L ^{-1} T \right] \)(2) \( \left[ M ^{0} L ^{-1}\right] \)(3) \( \left[ M ^{0} L ^{0} T ^{0}\right] \)(4) \( \left[ ML ^{-1} T \right] \) |
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Answer» Correct option is (1) We know that v = w/k \(\frac{1}{v}=\frac{k}{w}\) \(\frac{k}{w}=\frac{1}{[LT^1]}\) \(\frac{k}{w}=[L^{-1}T]\) |
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