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The velocity of a particle is `v = v_(0) + gt + ft^(2)`. If its position is ` x=0 ` at ` t= 0 `, then its displacement after unit time `( t = 1 )` isA. `( v_(0) + g//2 + f)`B. `( v_(0) + g//2 + 3f)`C. `( v_(0) + g/2 + (f )//(3)`D. `( v_(0) + g + f)` |
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Answer» Correct Answer - C We know that , ` v = (dx) /(dt) rArr dx = v dt)` Integrating , `int _(0)^(x) dx = int _(0)^(t) v dt ` or` x = int _(0)^(t) ( v_(0) + gt + ft^(2)) dt = [ v_(0)t (gt^(2)/(2) + (ft^(3)/(3) ]_(0)^(t) ` or, ` x = v_(0)t + (gt^(2))/(2) + (ft^(3))/(3) ` At ` t= 1, x = 0 v_(0) + (g)/(2) + (f)/(3)`. |
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