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The velocity of a particle moving in a straight line is decreasing at the rate of `3 m//s` per metre of displacement at an instant when the velocity is `10 m//s.` Determine the acceleration of the particle at this instant. |
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Answer» Correct Answer - B::C `(dv)/(ds)=-(3 m//s)/m` `a=v.(dv)/(ds)` `=(10)(-3)` `=-30 m//s^2` |
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