1.

The velocity of a particle performing S.H.M. are 0.13 m/s and 0.12 m/s. When it is at 0.12 m and 0.13 m from the mean position respectively. Then the amplitude isA. 0.117 mB. 0.177 mC. 11.7 mD. 10 m

Answer» Correct Answer - B
Tricks : `A=sqrt(v_(1)^(2)+v_(2)^(2))`


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