The velocity of a particle varies with time as per the law vec(V) = vec(a) + vec(b)t where vec(a) and vec(b) are two constant vectors. The time at which velocity of the particle is perpendicular to velocity of the particle at t= 0 is

The velocity of a particle varies with time as per the law vec(V) = ve

1.	The velocity of a particle varies with time as per the law vec(V) = vec(a) + vec(b)t where vec(a) and vec(b) are two constant vectors. The time at which velocity of the particle is perpendicular to velocity of the particle at t= 0 is
Answer» `-(\|VEC(a)\|)/(vec(a).vec(B))` `-(\|vec(a)\|^(2))/(vec(a).vec(b))` `-(vec(a).vec(b))/(\|vec(a)\|^(2))` NONE of these Answer :B