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The velocity of all radiowaves in free space is `3xx10^(8),//s`, the frequency of a wave of wavelength `150 m` isA. 20 khzB. 2 kHzC. 2 MHzD. 1 MHz |
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Answer» Correct Answer - C As given `E=10cos(10^(7)t+kx)` Comparing it with standard equation of e.m. wave, `E=E_(0)cos(omegat+kx)` Amplitude `E_(0)=10 V//m` and `omega=10^(7) rad//s` `because c=vlamda=(omegalamda)/(2pi)` Or `lamda=(2pic)/(omega)=(2pixx3xx10^(8))/(10^(7))=188.4m` Also, `c=(omega)/(K)` or `k=(omega)/(c)=(10^(7))/(3xx10^(8))=0.033` The wave is propagating along y direction. |
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